Q240944: BUG: ListView’s Left/Top Properties Return Unexpected Values
Article: Q240944
Product(s): Microsoft Visual Basic for Windows
Version(s): 6.0
Operating System(s):
Keyword(s): kbsample kbCmnCtrls kbCtrl kbListView kbVBp kbVBp600bug kbGrpDSVB kbDSupport
Last Modified: 23-MAR-2001
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The information in this article applies to:
- Microsoft Visual Basic Learning Edition for Windows, version 6.0
- Microsoft Visual Basic Professional Edition for Windows, version 6.0
- Microsoft Visual Basic Enterprise Edition for Windows, version 6.0
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SYMPTOMS
========
When the Left or Top property of the ListView control is assigned a negative
value, the result is a value greater by 1 pixel. Positive values return the
expected result.
RESOLUTION
==========
Step-by-Step Workaround
-----------------------
1. Start a new Standard EXE project in Visual Basic. Form1 is created by
default.
2. On the Project menu, click to select Components, check Microsoft Windows
Common Controls 6.0, and then click OK.
3. Draw a ListView control on Form1. On the Properties window, set View = 0 -
lvwSmallIcon.
4. Add the following code to the General Declarations section of Form1:
Option Explicit
Dim itm As ListItem
Private Sub Form_Click()
Dim sngLeft As Single
Dim sngTop As Single
Me.ScaleMode = vbPixels
sngLeft = -2
sngTop = -2
Set itm = ListView1.ListItems.Add(Text:="item")
' Inaccurate
itm.Left = sngLeft
itm.Top = sngTop
MsgBox "Left = " & itm.Left & " Top = " & itm.Top
' More accurate
LocateListItems itm, sngLeft, sngTop
MsgBox "Left = " & itm.Left & " Top = " & itm.Top
End Sub
Private Sub LocateListItems(item As ListItem, x As Single, y As Single)
Select Case x
Case Is < -1.5
x = x - 1
Case Is < 0
x = x - 1.1
Case Else
End Select
item.Left = x
Debug.Print "Item.Left = "; item.Left
Select Case y
Case Is < -1.5
y = y - 1
Case Is < 0
y = y - 1.1
Case Else
End Select
item.Top = y
Debug.Print "Item.Top = "; item.Top
End Sub
5. Run the project by pressing the F5 key, and note the results in the Immediate
window. Without correction, the inaccurate result is displayed. After a call
to the correcting function, the more accurate result is displayed.
STATUS
======
Microsoft has confirmed this to be a bug in the Microsoft products listed at the
beginning of this article.
MORE INFORMATION
================
Because these properties are for positions that are stored as real numbers, they
are usually not whole numbers. However, for any negative value that is assigned,
the result is always 1 pixel greater than the assigned value.
Steps to Reproduce Behavior
---------------------------
1. Start a new Standard EXE project in Visual Basic. Form1 is created by
default.
2. On the Project menu, click to select Components, check Microsoft Windows
Common Controls 6.0, and then click OK.
3. Draw a ListView control on Form1. On the Properties window, set View =
lvwSmallIcon.
4. Add the following code to the General Declarations section of Form1:
Private Sub Form_Click()
ListView1.ListItems(1).Left = -5
Debug.Print "Left = "; ListView1.ListItems(1).Left
ListView1.ListItems(1).Top = -5
Debug.Print "Top = "; ListView1.ListItems(1).Top
End Sub
Private Sub Form_Load()
Me.ScaleMode = vbPixels
Call ListView1.ListItems.Add(Text:="item")
End Sub
5. Run the project by pressing F5, click on the form, and note that this
produces the following output in the Immediate window:
Left = -3.968504
Top = -3.968504
6. Note that the result is 1 pixel greater than the assigned value.
Additional query words:
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Keywords : kbsample kbCmnCtrls kbCtrl kbListView kbVBp kbVBp600bug kbGrpDSVB kbDSupport
Technology : kbVBSearch kbAudDeveloper kbZNotKeyword6 kbZNotKeyword2 kbVB600Search kbVBA600 kbVB600
Version : :6.0
Issue type : kbbug
Solution Type : kbpending
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