Q168932: BUG: Multiple Based Conversion Results May Be Incorrect
Article: Q168932
Product(s): Microsoft C Compiler
Version(s): 2.0,2.1,2.2,4.0,4.1,4.2,5.0,6.0
Operating System(s):
Keyword(s): kbtool kbCompiler kbVC500bug kbVC600bug
Last Modified: 13-FEB-2002
-------------------------------------------------------------------------------
The information in this article applies to:
- Microsoft Visual C++, versions 2.0, 2.1, 2.2, 4.0, 4.1
- Microsoft Visual C++, 32-bit Enterprise Edition, versions 4.2, 5.0, 6.0
- Microsoft Visual C++, 32-bit Professional Edition, versions 4.2, 5.0, 6.0
- Microsoft Visual C++, 32-bit Learning Edition, version 6.0
- Microsoft Visual C++.NET (2002)
-------------------------------------------------------------------------------
SYMPTOMS
========
When you perform multiple conversions on pointers that are declared with the
__based keyword, that have the same base, and are compiled as C++, the
conversion results may be incorrect.
RESOLUTION
==========
To work around this problem, limit __based type conversions to one. The sample
code below demonstrates how to implement some workarounds.
STATUS
======
Microsoft has confirmed this to be a bug in the Microsoft products listed at the
beginning of this article.
MORE INFORMATION
================
Steps to Reproduce Behavior
---------------------------
/* Compiler options: Use .cpp extension or /Tp switch */
#include <stdio.h>
void *pBase = (void*)0x00010000;
void *pGlobal = (void*)0x00010000;
void __based(pBase)* SomeFunction()
{
static void* pv = (void*)0x00010000;
return( void __based(pBase)* )pv;
}
void main()
{
int __based(pBase)* test1;
/* The following conversion always fails. A possible
solution is to have SomeFunction() simply return a
void*.
*/
test1 = ( int __based(pBase)* )SomeFunction();
printf( "Conversion 1 = %08X, should be 00000000\n",
(unsigned long)test1 );
/* This conversion fails on some versions. In this
example, the double conversion isn't necessary.
*/
test1 = ( int __based(pBase)* )( (void __based(pBase)*)
((void*)0x00010000) );
printf( "Conversion 2 = %08X, should be 00000000\n",
(unsigned long)test1 );
/* This conversion always works.
*/
test1 = ( int __based(pBase)* )( ( void __based(pBase)* )
pGlobal );
printf( "Conversion 3 = %08X, should be 00000000\n",
(unsigned long)test1 );
}
Output:
Conversion 1 = FFFF0000, should be 00000000
Conversion 2 = 00010000, should be 00000000
Conversion 3 = 00000000, should be 00000000
Additional query words:
======================================================================
Keywords : kbtool kbCompiler kbVC500bug kbVC600bug
Technology : kbVCsearch kbVC400 kbAudDeveloper kbVC220 kbVC410 kbVC420 kbVC500 kbVC600 kbVC200 kbVC210 kbVC32bitSearch kbVCNET kbVC500Search
Version : :2.0,2.1,2.2,4.0,4.1,4.2,5.0,6.0
Issue type : kbbug
=============================================================================
THE INFORMATION PROVIDED IN THE MICROSOFT KNOWLEDGE BASE IS PROVIDED "AS IS" WITHOUT WARRANTY OF ANY KIND. MICROSOFT DISCLAIMS ALL WARRANTIES, EITHER EXPRESS OR IMPLIED, INCLUDING THE WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE. IN NO EVENT SHALL MICROSOFT CORPORATION OR ITS SUPPLIERS BE LIABLE FOR ANY DAMAGES WHATSOEVER INCLUDING DIRECT, INDIRECT, INCIDENTAL, CONSEQUENTIAL, LOSS OF BUSINESS PROFITS OR SPECIAL DAMAGES, EVEN IF MICROSOFT CORPORATION OR ITS SUPPLIERS HAVE BEEN ADVISED OF THE POSSIBILITY OF SUCH DAMAGES. SOME STATES DO NOT ALLOW THE EXCLUSION OR LIMITATION OF LIABILITY FOR CONSEQUENTIAL OR INCIDENTAL DAMAGES SO THE FOREGOING LIMITATION MAY NOT APPLY.
Copyright Microsoft Corporation 1986-2002.