Q65744: C 6.00 Fails to Generate Symbolic Info for ELSE IF Statement

Article: Q65744
Product(s): See article
Version(s): 6.00   | 6.00
Operating System(s): MS-DOS | OS/2
Keyword(s): ENDUSER | buglist6.00, S_CodeView | mspl13_c
Last Modified: 16-OCT-1990

The following code, when compiled with Microsoft C version 6.00 for
CodeView debugging, does not stop at breakpoints placed on the ELSE IF
line of code. Also, any attempt to step onto the line using the trace
or step command will skip over this line as if no executable code was
associated with it.

Sample Code
-----------

/* compile line = cl /Zi /Od file.c */

void main(void)
{
   int i=100;

   if (i==2);
   else if(i==7);  /* cannot stop on this line */
}

As can be seen by switching into mixed source/assembly mode, there is
executable code associated with the ELSE IF statement. And, if a
breakpoint is placed on one of the assembly instructions associated
with the ELSE IF line, execution will be able to stop on that
instruction demonstrating that the code is being executed.

The following are two possible workarounds to this problem:

1. Compile with the quick compiler, which generates the correct
   symbolic information (for example, cl /qc /Zi /Od file.c).

2. Put the ELSE and IF on separate source lines, as follows:

      ELSE
           IF(i==7);

This method allows stepping through the IF statement.

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