Q43913: C: Finding the Length of Double Precision Decimals

Article: Q43913
Product(s): See article
Version(s): 5.10   | 5.10
Operating System(s): MS-DOS | OS/2
Keyword(s): ENDUSER | SR# G890424-17022 s_quickc | mspl13_c
Last Modified: 22-MAY-1989

Question:

Is there a straightforward way to determine how many decimal digits
are required to fully represent the integer and fractional portions of
a double floating-point number?

Response:

The most straightforward method is to convert the double to a string,
locate the decimal point, and then calculate the length of the
substrings before and after it.

The following example demonstrates the technique:

        #include <stdio.h>
        #include <string.h>
        #include <ctypes.h>

        char str[30];
        double stuff;
        int dec_pos, places_after, places_before;

        ...

        sprintf(str, "%f", stuff);
        dec_pos = strcspn( str, "." );
        places_after = strlen( str ) - dec_pos - 1;
        places_before = dec_pos - !isdigit( str[0] );

The strcspn function returns the position in str at which "." is
found. The isdigit() function accounts for the presence or absence of
a minus or plus sign. The sequence of steps in the string "-1253.356"
results in the following values:

    dec_pos == 5
    places_after == (9 - 5 - 1) == 3
    places_before == (5 - 1) == 4

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